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1875-50x-x^2=0
We add all the numbers together, and all the variables
-1x^2-50x+1875=0
a = -1; b = -50; c = +1875;
Δ = b2-4ac
Δ = -502-4·(-1)·1875
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-100}{2*-1}=\frac{-50}{-2} =+25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+100}{2*-1}=\frac{150}{-2} =-75 $
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